25x^2=196

Solution for 25x^2=196 equation:

25x^2=196

We move all terms to the left:

25x^2-(196)=0

a = 25; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·25·(-196)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*25}=\frac{-140}{50}
=-2+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*25}=\frac{140}{50}
=2+4/5
$